-0.2x-2.3=-0.03x^2-2.6

Solution for -0.2x-2.3=-0.03x^2-2.6 equation:

-0.2x-2.3=-0.03x^2-2.6

We move all terms to the left:

-0.2x-2.3-(-0.03x^2-2.6)=0

We get rid of parentheses

0.03x^2-0.2x+2.6-2.3=0

We add all the numbers together, and all the variables

0.03x^2-0.2x+0.3=0

a = 0.03; b = -0.2; c = +0.3;
Δ = b2-4ac
Δ = -0.22-4·0.03·0.3
Δ = 0.004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{0.004}}{2*0.03}=\frac{0.2-\sqrt{0.004}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{0.004}}{2*0.03}=\frac{0.2+\sqrt{0.004}}{0.06}
$